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Friday, July 11, 2025
Leetcode 2942. Find Words Containing Character
Problem Statement:
2942. Find Words Containing Character
You are given a 0-indexed array of strings words and a character x.
Return an array of indices representing the words that contain the character x.
Note that the returned array may be in any order.
Initial Code:
class Solution {
public List<Integer> findWordsContaining(String[] words, char x) {
List<Integer> findWordsContaining = new ArrayList();
for (int i = 0; i < words.length; i++) {
if (words[i].contains(x)) {
findWordsContaining.add(i);
}
}
return findWordsContaining;
}
}Issue in the code -
new ArrayList() | - Should declare the type parameter: new ArrayList<>() (or new ArrayList<Integer>()) |
words[i].contains(x) | - String.contains() expects a CharSequence, but passed char. Need to convert the char to a String: |
Updated Code:
class Solution { public List<Integer> findWordsContaining(String[] words, char x) { List<Integer> findWordsContaining= new ArrayList<>(); for (int i=0;i<words.length; i++){ if(words[i].indexOf(x)!=-1){ findWordsContaining.add(i); } } return findWordsContaining; } }
Leetcode 2769. Find the Maximum Achievable Number
Problem Statement:
2769. Find the Maximum Achievable Number
Given two integers, num and t. A number x is achievable if it can become equal to num after applying the following operation at most t times:Increase or decrease x by 1, and simultaneously increase or decrease num by 1.
Return the maximum possible value of x.
Initial Code:
class Solution {
public List<Integer> findWordsContaining(String[] words, char x) {
List<Integer> findWordsContaining = new ArrayList();
for (int i = 0; i < words.length; i++) {
if (words[i].contains(x)) {
findWordsContaining.add(i);
}
}
return findWordsContaining;
}
}Issue in the code -
new ArrayList() | - Should declare the type parameter: new ArrayList<>() (or new ArrayList<Integer>()) |
words[i].contains(x) | - String.contains() expects a CharSequence, but passed char. Need to convert the char to a String: |
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